find the rate of energy radiated by a man by assuming the surface area of his body 1.7m²and emissivity of his body 0.4​

The rate of energy radiated by the man is 3.86 x  J/s. .

The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:

Q(t) = Aeσ

where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.

To determine the rate of energy radiated by the man in the given question;

= Aeσ

But A = 1.7 m², e = 0.4 and σ = 5.67 x J/s.

So that;

= 1.7 * 0.4 * 5.67 x

     = 3.8556 x

     = 3.86 x  J/s.

Thus, the rate of energy radiated by the man is 3.86 x  J/s. .

Learn more on energy radiation of objects by visiting:

snell's law

refractve index = sin incidence / sin refraction