In the diagram, q1 = +4.88*10^-8 C. What is the potential difference when
you go from point A to point B?
Include the correct sign, + or - .
B
0.538 m
1.36 m
91 |
(Hint: Does V go up or down when you go
from B to A?) (Unit = V)

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

Explanation:

The potential difference while moving from point A to Point B is given as follows:

where,

ΔV = potential difference from A to B = ?

= Potential at point A =

= Potential at point B =

Therefore,

where,

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q = magnitude of charge = 4.88 x 10⁻⁸ C

= distance of point A from charge = 1.36 m

= distance of point B from charge = 0.538 m

Therefore,

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

attach the statements so i can answer : )

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.