An object whose weight is 100 lbf experiences a decrease in kinetic energy of 500 ft lbf and an increase in potential energy of 1500 ft lbf. The initial velocity and elevation of the object, each relative to the surface of the earth, are 40 ft/s and 30 ft, respectively. If g 5 32.2 ft/s2 , determine: (a) the final velocity, in ft/s.
(b) the final elevation, in ft.

a)  

b)

Explanation:

From the question we are told that:

Weight

Decrease in kinetic energy

Increase in potential energy

Velocity

Elevation

a)

Generally the equation for Change in Kinetic Energy is mathematically given by

b)

Generally the equation for Change in Potential Energy is mathematically given by

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

your answer is, orbit around the nucleus