A heat-engine cycle is executed with steam in the saturation dome between the pressure limits of 7 MPa and 2 MPa. If heat is supplied to the heat engine at a rate of 150 kJ/s, the maximum power output of this heat engine is . Solve using appropriate software. Multiple Choice

19.72kW

Explanation:

At P1 = 7 MPa, the saturated temperature T1 = 285.83°C. This will be converted to Kelvin

= 285.83 + 273

= 558.83K

At P2 = 2 MPa, the saturated temperature T1 = 212.38°C. This will be converted to Kelvin

= 212.38 + 273

= 485.38K

Then, the maximum possible efficiency which is the Carnot efficiency will be:

= 1 - T2/T1

= 1 - 485.38/558.83

= 1 - 0.8686

= 0.1314

Then, the the maximum power output of this heat engine will be:

= 0.1314 × 150 kJ/s

= 19.72kW

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