• A car is initially traveling at 50.0 km/h. The brakes are applied and the car stops over a distance of 35 m. What was magnitude of the
car's acceleration while it was braking?

Explanation:

The equation for acceleration is

where vf is final velocity, v0 is initial velocity and t is time in seconds. But we have a problem here because the initial velocity is given in km/hr while the distance is given in meters. We are going to change 50.0 km/hr to m/sec:

which gives us an initial velocity of

v = 13.9 m/s

But that still doesn't give us anything for the time, which is the denominator of the acceleration equation. We have to find it. Since this is one-dimensional travel, use d = rt to find the time it took for the car to travel 35 meters at a rate of 13.9 m/s:

35 = 13.9t and

t = 2.5 seconds. Now we can use that in the acceleration equation:

so

a = -5.6 m/s/s The negative sign tells us that the car is slowing down, as we would expect it to be when it is traveling at a certain rate and eventually stops.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

he . if i may ask what i your question exactly?

explanation: