A student of weight 642 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude of the normal force Upper F Overscript right-arrow EndScripts Subscript Upper N on the student from the seat is 556 N. (a) What is the magnitude of Upper F Overscript right-arrow EndScripts Subscript Upper N at the lowest point

the answer is a 3.8cm

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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