9. Calculate the force of attraction between two masses, one of 3 kg and the other with a mass of 5.0 kg if they are 0.0225 m apart.

conservation of mass

mass before something happens = mass afterwards

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j