What is the amount of heat released when 0.8 kg of water at 25°C cools until it becomes ice at -6°C? State the assumptions you make in your calculations. [Specific heat capacity of water, Cwater = 4.2 x 10' J kg °C specific heat capacity of ice, Cice = 2.0 x 10' J kg-1 °C- and specific latent heat of fusion of ice, l = 3.34 x 10 J kg )​

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Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.