How long the period of the earth's circulation (365 1/4) in seconds?​

31,556,736 seconds

Explanation:

The period of Earth's orbit around the Sun, T = (365 + 1/4) days (three hundred and sixty five and a quarter days

The period of Earth's orbit around the Sun in seconds is given by converting, T = into seconds as follows;

There are 60 seconds per minute, 60 minutes in each hour, 24 hours within each day, therefore, we get;

T = ×60 sec/min × 60 min/hr. × 24hr/day = 31,556,736 seconds

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

pe = weightxheight = 2000x1000=2,000,000joules