An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.7 m/s . It then flies a further distance of 48500 m , and afterwards, its velocity is 44.7 m/s . Find the airplane's acceleration.

0.0095 m/s²

Explanation:

We have,

We are asked to calculate the airplane's acceleration.

By using the third equation of motion,

➝ v² - u² = 2as

➝ (44.7)² - (32.7)² = 2 × a × 48500

➝ 1998.09 - 1069.29 = 97000 × a

➝ 928.8 = 97000a

➝ 928.8 ÷ 97000 = a

➝ 0.0095 m/s² = a

the answer is b i think

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