An ice chest at a beach party contains 12 cans of soda at 3.78 °C. Each can of soda has a mass of 0.35 kg and a specific heat capacity of 3800 J/(kg C°). Someone adds a 6.48-kg watermelon at 29.4 °C to the chest. The specific heat capacity of watermelon is nearly the same as that of water. Ignore the specific heat capacity of the chest and determine the final temperature T of the soda and watermelon in degrees Celsius.

T = 13.25°C

Explanation:

From the law of conservation of energy:

Heat Lost by Watermelon = Heat Gained by Cans

where,

= mass of watermelon = 6.48 kg

= mass of cans = (12)(0.35 kg) = 4.2 kg

= specific heat capacity of watermelon = 3800 J/kg.°C

 = specific heat capacity of cans = 4200 J/kg.°C

= Change in Temprature of watermelon = 29.4°C - T

= Change in Temperature of cans = T - 3.78°C

T = final temperature = ?

Therefore,

T = 13.25°C

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

answer///scientific method;