Estimate the average force that a baseball pitcher's hand exerts on a 0.145-kg baseball as he throws a 39-m/s pitch. Assume the pitcher accelerates the ball through a horizontal distance of 2.0 m, from behind his body to where the ball is released and ignore the air resistance.

55 N

Explanation:

Assuming no potential energy changes.

The work applied increases the kinetic energy.

Fd = ½mv²

F = mv²/2d = 0.145(39²) / (2(2.0)) = 55.13625 ≈ 55 N

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