If 25 kg of ice at 0°C is combined with 4 kg of steam at 100°C, what will be the final equilibrium temperature (in °C) of the system?

The temperature of the final equilibrium temperature of the system is 19.7⁰C

Explanation:

Given;

mass of the ice, m₁ = 25 kg

temperature of the ice =  0°C

mass of the steam, m₂ = 4 kg

temperature of the steam, = 100 ⁰C

Let the temperature of the resulting mixture = t

Apply the principle of conservation of energy.

Heat required to melt the ice + Heat gained by the mixture = Heat required to convert the water to steam + Heat lost by the mixture

where;

Lf is the latent heat of fusion of ice =  3.33 x 10⁵ J/kg.

Lv is the latent heat of vaporization of water, = 2.260 x 10⁶ J/kg

c is the specific heat capacity of water = 4,200 J/kg

The temperature of the final equilibrium temperature of the system is 19.7⁰C

see earlier answer