A Bullet weighing 4.5 × 10-³kg is fired horizontally into a 1.8kg wooden block at rest on a horizontal surface. The coefficient of the kinetic friction between block and surface is 0.20 the bullet comes to rest in the block which moves 1.8m, find the speed of the bullet​

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

the answer is the last option

explanation:

because in order to know what the molecule is you need to know how many atoms of each element are in the molecule.