[2] 0.5m 0.25 e its mass 1 3 Total:[4] Figure 4.1 termined (a) What is meant by moment of force? Include its Sl unit? [2] (13) (c) Calculate the moment of force if a force of 10N is applied at point 1 to open or close the door en filled with Moment of force= [2]
(d) Explain why it is easier to open or close the door if the handle is fixed at point 1 than at point 2 or 3. 10 to be [2] Total:[4]​

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

2.6 and i can kick good lol