A resistor of 500Ω and one of 2000Ω are placed in series with a 60V supply. What will be the reading on a voltmeter of internal resistance 2000Ω when placed across (i) 500Ω resistor and (ii) 2000Ω resistor?

10 V, 40 V

Explanation:

Given

Resistors are and

Power supply

Voltmeter internal resistance

When it connected around resistance, effective resistance becomes

Total resistance in series

Current in circuit

Voltage around resistance is

(B) when voltmeter is connected around  resistor

Net resistance around it

Total resistance

Current in circuit

Voltage around resistor

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j