A solar-heated home has a tank of Glauber's salt in the basement. Its purpose is to store 2.8 X 10'J of heat energy,, and it can be
heated from 28°C to 50°C. The melting point of Glauber's salt is 32°C
and it has a specific latent heat of fusion of 241 kJ/kg. Its specific heat
capacity as a solid is 1066 J/(kg °C) and 1576 J/(kg °C) for its liquid
state. Calculate the mass of Glauber's salt required to store this heat.(8)

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .