Physics, 19.06.2021 05:10 Seaisnowblue

Hai điện tích điểm bằng nhau đặt trong chân không cách nhau một khoảng R1 = 4 cm lực đẩy giữa chúng là F1 = 9 nhân 10 mũ trừ 5 niutơn để lực tác dụng giữa chúng là F2 = 1,6 nhân 10 mũ trừ 4 n thì khoảng cách R2 giữa điện tích đó phải bằng bao nhiêu

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Hai điện tích điểm bằng nhau đặt trong chân không cách nhau một khoảng R1 = 4 cm lực đẩy giữa chúng...