Ples helppp me this is timedd

50 km/h

Explanation:

From the graph, we can deduce the following parameters;

Distance = 20, 40, 60, 80, 100 km

Time = 0.5, 1.0, 1.5, 2.0 hours

To find the average velocity of the car over the first 2.00 hours.

First of all, we would determine the total distance and time.

Total distance = 20 + 40 + 60 + 80 + 100 = 300 km

Total time = 0.5 + 1.0 + 1.5 + 2.0 = 5

Average velocity = distance/time

Average velocity = 100/2

Average velocity = 50 km/h

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

i'm on my way to history not a mistory.