Justhin and Christian have masses of 74 kg and 64 kg, respectively. They stand 0.5 m apart. If there were no other forces acting on them, what gravitational force would they be exerting on each other?

ans: 1.26 × 10^(-6) N

Explanation:

suppose that;

mass of Justhin ( m) = 74 kg

mass of Christian (M) = 64 kg

distance of separation (d) = 0.5 m

universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²

so,

gravitational force between them(F) = GmM/d²

F = (6.67 × 74× 64)/ ( 10¹¹× 0.5²)

= (1.26 × 10⁵)/ 10¹¹

= 1.26 × 10^(-6) N

d.7.5cm is your answer

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.