Two cars, A and B , are travelling in the same
direction
although
Car B is 186 metres behind A. The
speed car B is 24.4 m/s and the speed of car A is 18.6 m/ s. How much time does it take for car B to catch up with car A?

SA = 18.6 * t + 186    total distance traveled by A in time t

SB = 24.4 t                total distance car B must travel to catch car A

SA - SB = 0 = 18.6 t + 186 = 24.4 t

(24.4 - 18.6) t = 186

t = 186 m / 5.8 m/s = 32 s

Check 18.6 * 32 + 186 = 781 m

24.4 * 32 = 781 m

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.