A spring that obeys Hooke's law has a spring force constant of 266 N/m. This spring is then stretched by 28.4 cm. (a) What is the magnitude of the force required to stretch the spring by this distance

75.544 N.

Explanation:

From Hooke's law,

Applying,

F = ke Equation 1

Where F = Force required to stretch the spring, k = force constant of the spring, e = extension.

From the question,

Given: k = 266 N/m, e = 28.4 cm = 0.284 m

Substitute these values into equation 1

F = 266(0.284)

F = 75.544 N.

Hence the force required to stretch the spring is 75.544 N

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

yup its correct its: c) b b