The velocity of particle varies with time as equation v=3tî - 2tj The acceleration of particle at t= 1 s is​

Velocity of a particle varies with its displacement as v = ( √(9 ... Velocity of a particle varies with its displacement as v = ( √(9 - x^2) ) m/sFind the magnitude of maximum acceleration of the particle.

Don't know if you meant to write 3t²i - 2tj

If so

a=dv/dt = 6ti - 2j

at t=1sec

a = 6(1)I - 2j

a=6i - 2j

Magnitude of a = √6²+(-2)²

a= 2√10ms-²

or 6.32ms-².

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

need to see circuit to get time constant