The center-to-center distance between a 200-g lead sphere and an 800-g lead sphere is 0.120 m. A 1.00-g object is placed 0.0800 m from the center of the 800-g sphere along the line joining the centers of the two spheres.
(a) Ignoring all sources of gravitational force except the two spheres, calculate the gravitational force exerted on the object.
(b) Determine the gravitational potential energy per gram at the position of the object.
(c) How much work is needed to bring the object 0.0400 m closer to the 800-g sphere?
Answers: 2
Other questions on the subject: Physics
Physics, 21.06.2019 21:20, janayshas84
An artificial satellite circles the earth in a circular orbit at a location where the acceleration due to gravity is 6.03 m/s^2. determine the orbital period of the satellite.
Answers: 3
Physics, 22.06.2019 01:30, ayalat9596
An object of dimensions 50 cm x 40 cm x 0.20 cm has a mass 60g. find its density in g/cm3 and kg/ m3
Answers: 1
Physics, 22.06.2019 16:30, yagalneedshelp8338
Acalorimeter uses the principle that thermal energy flows from hotter material to colder material until both reach the same
Answers: 1
Physics, 22.06.2019 17:50, supasavb99
Convection occurs when thermal energy is transferred by the movement of
Answers: 1
You know the right answer?
The center-to-center distance between a 200-g lead sphere and an 800-g lead sphere is 0.120 m. A 1.0...
Questions in other subjects:
Mathematics, 20.04.2020 22:34
Mathematics, 20.04.2020 22:34
Biology, 20.04.2020 22:34
