(b) During one day, 250 kg of water is pumped through the solar panel. The température of this
water rises from 16°C to 38°C.
The water absorbs 25% of the energy incident on the solar panel. The
specific heat capacity
of water is 4200J/(kg °C).
Calculate the energy incident on the solar panel during that day.
Please explain how to find the incident energy

The energy incident on the solar panel during that day is .

Explanation:

Given: Mass = 250 kg

Initial temperature =

Final temperature =

Specific heat capacity = 4200

Formula used to calculate the energy is as follows.

where,

q = heat energy

m = mass of substance

C = specific heat capacity

= initial temperature

= final temperature

Substitute the values into above formula as follows.

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

Thus, we can conclude that the energy incident on the solar panel during that day is .

12000j is work done

massxgravity x heght=weightxheight= pe

4900=490xh

h=10