How far will a brick starting from rest fall freely in 3 seconds

When object falls freely we can say

its initial speed will be ZERO

and its acceleration due to gravity must be

a = g = 9.8 m/s^2a=g=9.8m/s2

Now we need to find the distance of free fall in 3 s of time

So here we will use kinematics

y = v* t + \frac{1}{2} at^2y=v∗t+21at2

now we will plug in all values in it

y = 0 + \frac{1}{2}* 9.8 * 3^2y=0+21∗9.8∗32

y = 44.1 my=44.1m

So it will fall by total distance of 44.1 m

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.