How many heat is needed to melt 1.5kg of ice and then to raise the temperature of the resulting water 50 degree Celsius ​

• The amount of heat required to melt ice and raise the temperature of water T^oCToC is

Q=mL_f+mc\Delta TQ=mLf+mcΔT

Here m=1.5 kgm=1.5kg

L_f=3.33*10^5 J/kgLf=3.33∗105J/kg is Latent heat of fusion of ice.

c=4186 J/kg.^oCc=4186J/kg.oC is heat capacity of water.

\Delta T=50 ^oC-0^oC=50^oCΔT=50oC−0oC=50oC

So,

Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 JQ=(1.50)[3.33∗105+(4186)(50)]=8.13∗105J

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.