A uniform solid disk (=1/2^2) and a hoop (=^2) with different masses and radii are placed at the top of an inclined plane. They are both released from rest and then roll without slipping. What is the ratio of the speed of the hoop to the speed of the disk at the bottom of the inclined plane?

nah.   i'm just sleepy.

a 2,000 calorie based diet.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft