A projectile is launched from the ground with an initial horizontal velocity of 6.0m/s [right] and an initial vertical velocity of 5.0/s [up]. At what angle from vertical is it launched?

θ = 39.8°

Explanation:

Her, we will use the trigonometric ratio of the tangent to find the launch angle of the projectile from the vertical:

where,

θ = launch angle from the vertical = ?

vy = vertical component of velocity = 5 m/s

vx = horizontal component of velocity = 6 m/s

Therefore,

θ = 39.8°

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

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