Applicable Equations ΣIin = ΣIout of a junction
V = IR
ΣV = 0 in a loop

You will get 0.25 points each for providing the correct numerical answers with their respective units in the table.
You will get one point each for properly identifying how to use Kirchhoff’s first law, Kirchhoff’s second law, and Ohm’s law. To get the full 3 points for this section you must do one of the following:
A: Fill in the table with the correct numerical values of potential, current, or resistance that is missing.
-OR-
B: If you prefer to answer qualitatively or you are not sure of your algebra you may qualitatively explain how to apply Kirchhoff’s 1st and 2nd laws as well as Ohm’s law.
If you can accurately complete the table you do not have to provide any qualitative explanation.

Conceptualize notice how this problem differs from our previous discussion of gauss's law. the electric field due to point charges was discussed in the previous section. now we are considering the electric field due to a distribution of charge. we found the field for various distributions of charge in the chapter entitled electric fields by integrating over the distribution. this example demonstrates a difference from our discussions in the previous chapter. in this chapter, we find the electric field using law. categorize because the charge is distributed uniformly throughout the sphere, the charge distribution has spherical symmetry and we can apply gauss's law to find the field. analyze note that the following conditions can be used to determine a suitable gaussian surface. condition (1): the value of the electric field can be argued by symmetry to be constant over the portion of the surface. condition (2): the dot product e â· da can be expressed as a simple algebraic product e da because e and da are parallel.