What is the electric field at a point 0.300 m to the right of a
-4.77*10^-9 C charge?
Include a + or - sign to indicate the
direction of the field.

E = -477 N/C

Explanation:

Given that,

Charge,

We need to find the electric field at a point 0.3 m to the right of the charge.

We know that the electric field at a distance r is given by :

So, the electric field is -477 N/C.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.