A bucket filled with water has a mass of 20.0 kg and is attached to a rope, which in turn, is wound around a 0.050-m radius cylinder at the top of a well. What torque does the weight of water and bucket produce on the cylinder if the cylinder is not permitted to rotate

The torque produced is 9.8 Nm.

Explanation:

Given;

mass of the bucket filled with water, m = 20 kg

radius of the cylinder, r = 0.05 m

The torque produced by the weight of water and bucket is the product of force and the perpendicular distance from a point on the line of action of the applied force. (since the cylinder is not permitted to rotate).

τ = F x r

τ = (mg) x r

τ = (20 x 9.8) x 0.05

τ = 9.8 Nm

Therefore, the torque produced is 9.8 Nm.