A student fills a tank of radius r with water to a height of h1 and pokes a small, 1.0 cm diameter hole at a distance h2 from the bottom of the tank. The water flows out of the small hole into an empty, 0.2 m-diameter container placed below the tank. The student uses a garden hose to keep the water level in the tank at the original height. h1 = 0.50 meters, h2 = 0.03 meters. The garden hose used to keep the tank full has a diameter of 1 inch which is exactly 0.0254 meters

Required:
a. What is the velocity of the water as it leaves the hole near the bottom of the tank?
b. What is the volume flow rate of water from the garden hose into the tank?
c. After 60 seconds of operation, what is the water pressure at the bottom of the container that is being used to catch the water leaving the tank?

Need only answer if you think you know it

Amass m = 74 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius r = 18.4 m and finally a flat straight section at the same height as the center of the loop (18.4 m off the ground). since the mass would not make it around the loop if released from the height of the top of the loop (do you know why? ) it must be released above the top of the loop-the-loop height. (assume the mass never leaves the smooth track at any point on its path.) 1. what is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? 2. what height above the ground must the mass begin to make it around the loop-the-loop? 3. if the mass has just enough speed to make it around the loop without leaving the track, what will its speed be at the bottom of the loop? 4. if the mass has just enough speed to make it around the loop without leaving the track, what is its speed at the final flat level (18.4 m off the ground)? 5. now a spring with spring constant k = 15600 n/m is used on the final flat surface to stop the mass. how far does the spring compress?

Galileos view of arrangement of the universe