Physics, 13.05.2021 17:30 qais8691

Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct? No, a weak or a strong force applied to the ball is unable to affect the motion of the ball. No, the force applied to the bowling ball should be a strong force. Yes, the force applied to the bowling ball affects the motion of the ball. Yes, the ball will travel a longer distance when a weak force is applied.

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Answer from: KP1998

I would like to attach options to the question above for clarity.

Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct?

A. No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.

B. No, the force applied to the bowling ball should be a strong force.

C. Yes, the force applied to the bowling ball affects the motion of the ball.

D. Yes, the ball will travel a longer distance when a weak force is applied.

The correct option is C (Yes, the force applied to the bowling ball affects the motion of the ball).

Explanation:

First, a force is any effort either push or pull that causes an object to undergo a change.

A bowling ball can remain at rest or in motion except a force acts on it. This brings us to the question above, the mass which affects force is not mentioned which means it is uniform or negligible. Recall that force = mass X acceleration. So the greater the force that is applied to the bowling ball the further distance it will travel. From the question, she applied a forward force (pushing), so the more force she applies the further the bowling ball will travel.

Answer from: Quest

weight of the box is given as

$w = 112.1 n$

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

$w_x = w sin\theta$

here we have

$w = 112.1 n$

$w_x = 112.1 sin42$

$w_x = 75 n$

so it requires 75 n force to move it upwards

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .