During a tug-o-war, Team A members pulled with the following forces: 34N, 28N, 40N, 44N. Members of Team B pulled with the following forces: 32N, 49N, 38N, and 39N. Which team won and what was the net force on the rope?

B, if it was a lower watt she could put it in for her normal time and not burn it

Milliseconds. . . . . .

No because scientist are still changing there mines today so they are not correct to this day

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j