In the previous problem you found out that that the ratio between Enterprise's speeds at points A and B on the elliptical (transfer) orbit is 1/3. Since there are no forces acting on the Enterprise Earth system the total mechanical energy of the system is conserved while Enterprise is moving on the elliptical orbit. The total energy in points A and B is the same. Find the entrance speed (vA ) and exit speed (vB ) the Entreprise must match exactly in order to leave the outer circular orbit and engage onto the inner circular orbit. Give your answer in terms of G, ME and R. Enter a comma between the two expressions