Calculate the rate constant for the first-order decay of 24na (t1/2 = 14.7 h).

This problem is pretty straight forward since we are given the half time and we simply have to find for the rate constant. The equation relating the two variable is:

t1/2 = ln(2) / k

where k is the rate constant, therefore:

k = ln(2) / t1/2

k = ln(2) / 14.7 h

k = 0.047 / hour

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y