Physics, 02.10.2019 05:00 lovelarissa

You drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min. what is the average speed?

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To answer this question, you need to count the total distance traveled. The calculation would be:
Total distance = v1 * t1 + v2*t2= 20m/s * 10 min * 60 sec/min + 34 m/s * 10 min * 60 sec/min= 12000m+20400m= 32400m.

Then you need to divide the distance with the total time to find the average speed.
It would be: 32400m/ (10min+10min)= 32400m/20min * 1 min/60sec= 27m/s

Answer from: adamflex

The average speed when I drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min is 27 m/s

Average speed: Thes can be defined as the ratio of the total distance to the total time traveled by a body.

The question above can be solved using the formula below

S = D/T Equation 1

Where S = Average speed, D = Total distance, T = total time

For the first case,

d₁ = s₁×t₁

Given: s₁ = 20 m/s, t₁ = 10 min = 10×60 = 600 s

d₁ = 20(600)

d₁ = 12000 m.

For the second case,

d₂ = s₂×t₂ Equation 2

Given: s₂ = 34 m/s, t₂ = 10 min. = 600 s

d₂ = 34(600)

d₂ = 20400 m

Therefore,

Total distance (D) = 12000+20400

D = 32400 m

Total distance (T) = 600+600 = 1200 s

S = 32400/1200

S = 27 m/s

Hence, What is the average speed is 27 m/s

Learn more about average speed here: link

Answer from: Quest

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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You drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min. what i...