The volume of an ideal gas in a container is 2.0 l. what will be the volume of the gas if the pressure on the container is doubled while the temperature is reduced from 400 k to 200 k? a. 0.5 l b. 2.0 l c. 4.0 l d. 8.0 l

V₁ = initial volume of the gas = 2.0 L

P₁ = initial pressure on the container

T₁ = initial temperature = 400 K

V₂ = final volume of the gas = ?

P₂ = final pressure on the container = 2 P₁            (Since pressure is doubled)

T₂ = final temperature = 200 K

Using the equation

P₁ V₁/T₁ = P₂ V₂/T₂

inserting the values

P₁ (2)/(400) = (2P₁) V₂/(200)

(2)/(400) = (2) V₂/(200)

V₂ = 0.5 L

Hence the correct choice is

A. 0.5 L

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