Velocity graph of a particle moving along the x-axis. its initial position is x0 =2m at t0 = 0. at t = 3 s , what are the particle's (a) position, (b) velocity, and (c) acceleration?

t=0 y(2)=Y0 + V0t=(2m)+(4m/s)2sec=2+8=10m a=vf - vc / tf - tc = 0 - 4 / 4 - 2 = -2m/s^2 so a(3)= -2m/s2 v(3)= 2m/s2 (either directly from graph or v= vo + at = (4) + (-2)(1) = 4 - 2 =2m/s x(3)=x(2) + v(2) deltat + 1/2 adelta t^2 =(10m)+(4m/s)(1sec) + 1/2(-2m/s^2) (1sec) =10m +4m -1m = 14m - 1m x(3)=13m

Iwould sure like to answer your question but i honestly just don’t know