8. a 740 kg car traveling 19 m/s comes to a complete stop in 2.0 s. what is the force exerted on the car during this stop?

Force = mass * acceleration 

acceleration = change_in_velocity / time

so:

force = 740 kg * (19 m/s - 0 m/s) / 2.0 s
= 740 * 19 / 2 kg m per second^{2}
= 7030 kg m per second^{2}
= 7030 newtons of force

Iwannasay c is the most accurate