Suppose a scientist were to drop a cannonball from the leaning tower of pisa from a height of 180 ft. which expression could be used to determine how long, in seconds, it would take the cannonball to hit the ground?

The vertical height is h = 180 ft
The acceleration due to gravity is g = 32.2 ft/s²

Let t = the time for the cannonball to hit the ground.
Because the initial vertical velocity is zero (the ball is dropped), the formula to use is
h = (1/2)gt²

That is
t = √[(2h)/g]
  = √[(2*180)/32.2]
  = 3.344 s

The formula is , and the time is  3.344 s

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward