Abasketball player jumps straight upward. after 0.625 s, she is 0.411 m above the ground. what was her initial velocity?
use the formula
trianglex = vi * t+ 1/2g * t^2

Formula for the height is:
h = v i · t - 1/2 g · t²    ( minus sign because the gravitational force is in the opposite direction then the force that a player exerts )
0.411 = v i · 0.625 - 1/2 · 9.81 · 0.625²
0.411 = 0.625 v i - 1.916
0.625 v i = 0.411 + 1.916
0.625 v i = 2.327
v i = 2.327 : 0.625 = 3.72 m /s
Her initial velocity was 3.72 m/s.

I'm having some difficulty seeing the diagram clearly.but the question says there's a net inward force on the object.so we know right away,  from newton's 2nd law of motion, thatthat baby is accelerating.  it doesn't even matter which way thenet force is pointing.  if there's any net force, then either theobject's speed or else its direction must be changing.