Under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?

if there are no external forces acting on the object

Explanation:

under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?

If gravity and the normal reaction force are the only forces acting on the body, and the body is at rest or moving at constant velocity, the normal force and the weight are equal and opposite. Also if there are no influence of external forces

and air resistance is negligible.

from newtons law of motion which states that the rate of change in momentum is directly proportional to the force applied

f=km(v-u)/t

f=kma

where k is the constant and  equal to 1

f=ma

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.