Acar moving at 10 m/s crashes into a tree and stops in 0.26 s. calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. the mass of the passenger is 70 kg

We have that for the Question,it can be said that the force the seat belt exerts on a passenger in the car to bring him to a halt is

F_net=2.7*10^3

From the question we are told

A car moving at 10 m/s crashes into a tree and stops in 0.26 s. calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. the mass of the passenger is 70 kg

Generally the equation for the net Force  is mathematically given as

Therefore

the force the seat belt exerts on a passenger in the car to bring him to a halt is

F_net=2.7*10^3

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-2695 N

Explanation:

first of all, we need to calculate the acceleration experienced by the car and the passenger. This acceleration is given by

where

v=0 is the final velocity of the car, after the impact

u=10 m/s is the initial velocity

t=0.26 s is the duration of the collision

Substituting numbers into the formula,

The force exerted on the passenger is given by the product between the mass of the passenger (70 kg) and the acceleration:

where the negative sign means that the direction of the force is opposite to the motion of the passenger+car.