If a spring stores 33.5 j of energy when it's compressed by 0.13 m, what is the spring constant of the spring?

Energy, in terms of work, is expressed in units of Joules. Work is also force times distance. From work, we could then find the value of the force:

W = Fd
33.5 = Force x 0.13 m
F = 257.69 N

Apply Hooke's law then. Hooke's law is expressed as Force = k(delta x). From here we could determine the value of the spring constant:

257.69N = k x 0.13m
k = 1982.23 N/m

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !