Abeam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. if the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? the value of q = -1.6 × 10-19 coulombs.
(a)-2.9 × 106 n
(b)-3.9 × 10-14 n
(c)-4.9 × 10-14 n
(d)-6.5 × 10-13 n

Hello! 

F = Bqv sin theta F=Force B=magnetic flux density q=charge v=velocity theta=angle the moving electrons make with the magnetic field.

^^^You will find the force using that formula^^^

In Short, your Answer would MOST LIKELY have to be "B".

"-3.9 × 10-14 N"

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The magnets would be | n s | and | s n|