An airplane travels to the south at 968 km/h for 2.50 hours. the same airplane lands, and then takes off again, turning north and traveling at 875 km/h for 1.75 hours, whereupon it again lands. what is the airplane's average velocity for this trip?

The correct answer is  209.12 km/h.

Explanation:

The expression for the average velocity is as follows;

It is given in the problem that an airplane travels to the south at 968 km/h for 2.50 hours. The same airplane lands, and then takes off again, turning north and traveling at 875 km/h for 1.75 hours.

Calculate the total time taken by airplane.

t= 2.50 h+ 1.75 h

t= 4.25 h

Calculate the distance when an airplane travels to the south.

d'= st

Here, s is the speed and t is the time taken

Put s= 968 km/h and t= 2.50 h.

d'= (968)(2.50)

d'= 2420 km

Calculate the distance when an airplane travels to the north.

d''= st

Here, s is the speed and t is the time taken

Put s= 875 km/h and t= 1.75 h.

d''= (875)(1.75)

d''= 1531.25 km

Calculate the total displacement.

d= d'-d''

Put d'= 2420 km and d''= 1531.25 km.

d= (2420)- (1531.25)

d= 888.75 km

Calculate the the average velocity of the airplane.

Put  Total displacement, d= 888.75 km and t= 4.25 h

Average velocity= 209.12 km/h

Therefore, the airplane's average velocity for this trip is 209.12 km/h.

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