10 points.) a stone weighing 0.7 kilograms rolls down the inclined plane from position b to position a. position a is located at sea level. the inclined plane is 0.25 meters high. the difference in the gravitational potential energy of the ball between positions a and b is joules. (use pe = m × g × h, where g = 9.8 n/kg.)

Answer : 1.715 J

Explanation :

It is given that :

Mass of stone, m = 0.7 kg

The ball rolls down the inclined position from B to A and position A is located at sea level.

Height of inclined plane, h = 0.25 m

Gravitational potential energy at point A = 0 ( since, at point A PE = 0 )

Gravitational potential energy at point B = m g h

where,

m is the mass of ball

g is acceleration due to gravity

h is the height

So, at B potential energy will be :

So, the difference in the gravitational potential energy of the ball between positions A and B is :

Hence, this is the required solution.

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