The human body obtains 915 kj of energy from a candy bar. if this energy were used to vaporize water at 100.0 °c, how much water (in liters) could be vaporized? (assume the density of water is 1.00 g> ml.

0.403 liters of water could be vaporized

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

Q = Energy ( Joule )

m = Mass ( kg )

c = Specific Heat Capacity ( J / kg°C )

Δt = Change In Temperature ( °C )

Let us now tackle the problem!

Given:

heat added = Q = 915 kJ = 9.15 × 10⁵ J

specific latent heat of vaporization of water = Lv = 2268 J/g

density of water = 1.00 g/mL

Asked:

volume of water = V = ?

Solution:

We will use latent heat of vaporization formula to solve this problem as follows:

Next, we will calculate the volume of water by using density formula as follows:

Grade: College

Subject: Physics

Chapter: Thermal Physics

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water

answer///scientific method;